DIRECTIONS : Insert the missing number
| 6. | 9, 12, 11, 14, 13, ..., 15 |
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| A. 12 | B. 16 |
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| C. 10 | D. 17 |
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| Solution |
| 16. |
| Alternately we add 3 and subtract 1. |
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| 7. | 1, 2, 4, 8, 16, 32, 64, ..., 256 |
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| A. 128 | B. 148 |
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| C. 154 | D. 164 |
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| Solution |
| 128. |
| Each Previous number is multiplied by 2. |
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| 8. | 165, 195, 255, 285, 345, ... |
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| A. 375 | B. 420 |
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| C. 435 | D. 390 |
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| Solution |
| 435. |
| Each number is multiplied by a prime number i.e., 15x11, 15x13, 15x17 ... So, the next number is 15x29=435. |
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| 9. | 3, 4, 7, 16, 43, 124, ... |
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| A. 367 | B. 356 |
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| C. 125 | D. 1222 |
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| Solution |
| 367. |
| Each successive no. is obtained by first multiplying the previous by 3 and then subtracting 5. |
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| 10. | 3, 7, 6, 5, 9, 3, 12, 1, 15, ... |
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| A. 18 | B. 13 |
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| C. -1 | D. 3 |
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| Solution |
| -1. |
There are two series, beginning respectively with 3 and 7. In one 3 is added and in another 2 is subtracted. The next number is
1 - 2 = -1. |
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