APTITUDE | ARITHMATICAL | AREA | PROBLEMS BASED ON AREA 1

DIRECTIONS : Problems based on area.

1.	A rectangular parking space is marked out by painting three of its sides.If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, then what is the area of the parking space in square feet?
	A.  46	B.  81
	C.  126	D.  252 litres

Solution

Clearly,we have l=9 and l+2b=37 Area = (l x b) =(9 x 14) sq.ft = 126 sq.ft.

2.	The length of a rectangulat plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
	A.  40	B.   50
	C.  200	D.  120

Solution

Let breadth = x metres Then, length = (x + 20)metres. Perimeter = (5300 / 26.50) m = 200m

3.	The breadth of a rectangular field is 60% of its length. If the perimeter of the field is 800 m.What is the area of the field?
	A.  18750 sq.m	B.  37500 sq.m
	C.  40000 sq.m	D.  48000 sq.m

Solution

So length =250 m;breadth=150 m Area = (250 x 150)m² = 37500 m²

4.	The length of a rectangualr hll is 5m more than its breadth. The area of the hall is 750 m. The length of the hall is
	A.  15 m	B.  22.5 m
	C.  25 m	D.  30 m

Solution

Let the length = xmetres. Then length = (x +5)metres. Then,x(x +5)= 750 = x² + 5x - 750= 0 (x+30)(x-25)= 0 x=25.

5.	The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field?
	A.  15 metres	B.  26 metres
	C.  34.5 metres	D.  None of these

Solution

` Let breadth =x metres. Then length =(115x/100)metres. =(x) x(115 /100)= 460 x²=(460 x 100/115). x²=400 x= 20.